Sum of digits of a five digit number in c hackerrank solution

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For example, 5 / 3 = 1. To get the last digit of a number in base 10, use 10 as the modulo divisor. Task. Given a five digit integer, print the sum of its digits. Input Format. The input contains a single five digit number, n. Constraints. 10000 <= n <= 99999. Output Format. Print the sum of the digits of the five digit number.

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The three digit number XYZ when divided by 8, gives as quotient the two digit number ZX and remainder Y. The number XYZ is _____. Solution: NMTC 2019 Question Paper With Solutions Junior Level Ques No 17: The digit sum of any number is the sum of the digits. N is a 3 digit number.

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Then, sumDigits would go to the else case, add 5 to the sum then it would call sumDigits with 5 and the increased sum. This is an infinite loop. This is an infinite loop. You need to modify n before the next recursive call (hint: decimal point needs to be moved over by one). Leave a Comment / C, C Programs / By Niraj Kumar. In this post, we will learn how to check whether a number can be expressed as the sum of two prime numbers using C Programming language. For example: If we take the number 34, it can be expressed as sum of two prime numbers in the following ways: Sum of 3 and 31. Sum of 5 and 29. Sum of 11 and 23.

General Algorithm for sum of digits in a given number: Get the number. Declare a variable to store the sum and set it to 0. Repeat the next two steps till the number is not 0. Get the rightmost digit of the number with help of the remainder '%' operator by dividing it by 10 and add it to sum.The sum of the digits of x mod 9 is also x mod 9, which is why the sum is 0 mod 9 when x = n! for n >= 6. The alternating sum of the digits of x mod 11 equals x mod 11. The problem is that if you want the sum of the digits of a large number, not modulo anything, the tricks from number theory run out pretty quickly.General Algorithm for sum of digits in a given number: Get the number. Declare a variable to store the sum and set it to 0. Repeat the next two steps till the number is not 0. Get the rightmost digit of the number with help of the remainder '%' operator by dividing it by 10 and add it to sum.